mamoon Posted July 20, 2005 Share Posted July 20, 2005 ekvationen (x^3 -ax^2+ax+5=0)har en lösning x=-1 bestäm konstanten a. Hur lösar vi den? Link to comment Share on other sites More sharing options...
mambofeber Posted July 20, 2005 Share Posted July 20, 2005 x^3 -ax^2+ax+5=0 >> -1^3 -(a * -1^2) + (a * -1) + 5 = 0 räknar ut det i paranteserna först -1^3 -(a) + (-a) + 5 = 0 >> -1 - a - a + 5 = 0 >> -2a + 4 = 0 >> 4 + 0 = 2a a=2 Link to comment Share on other sites More sharing options...
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